NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3

eSchool July 03, 2020 CBSE Class 6 Maths

Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3.

  • Practical Geometry Class 6 Ex 14.1
  • Practical Geometry Class 6 Ex 14.2
  • Practical Geometry Class 6 Ex 14.4
  • Practical Geometry Class 6 Ex 14.5
  • Practical Geometry Class 6 Ex 14.6

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 14
Chapter NamePractical Geometry
Exercise Ex 14.3
Number of Questions Solved2
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3

Ex 14.3 Class 6 Maths Question 1.
Draw any line segment \overline { PQ }. Without measuring \overline { PQ }, construct a copy of \overline { PQ }.
Solution:
Steps of Construction:
Let PQ be the given line segment and l be a given line.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 13

  1. Mark a point 0 on the line l.
  2. Open out the compasses and adjust so that the steel end is on A and the pencil end is A on B.
  3. Transfer the compasses to the line l without disturbing their opening so that the steel end is on 0.
  4. With the pencil end make a small stroke on the line l to cut it at the point P.
    Then, the fine segment OP so obtained = the given line segment AB.

Ex 14.3 Class 6 Maths Question 2.
Given some line segment \overline { AB }, whose length you do not know, construct \overline { PQ } such that the length of \overline { PQ } is twice that of \overline { AB }.
Solution:
Steps of Construction:
Let AB be the given line segment.

  1. Draw any line l and make a point 0 on it.
  2. Open out the compasses in such way that the steel end is on A and the pencil end is on B.
  3. Transfer the compasses without disturbing their opening to the line l so that the steel end is on O.
  4. With the pencil end make a small stroke on -the line l to cut it at the point P.
  5. Repeat the steps 3 and 4 with same opening having P as the initial point and Q as the terminal point.
    Then, the segment OQ = OP + PQ = AB + AB= 2 AB.

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