# Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3.

• Practical Geometry Class 6 Ex 14.1
• Practical Geometry Class 6 Ex 14.2
• Practical Geometry Class 6 Ex 14.4
• Practical Geometry Class 6 Ex 14.5
• Practical Geometry Class 6 Ex 14.6

 Board CBSE Textbook NCERT Class Class 6 Subject Maths Chapter Chapter 14 Chapter Name Practical Geometry Exercise Ex 14.3 Number of Questions Solved 2 Category NCERT Solutions

## NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3

Ex 14.3 Class 6 Maths Question 1.
Draw any line segment $\overline { PQ }$. Without measuring $\overline { PQ }$, construct a copy of $\overline { PQ }$.
Solution:
Steps of Construction:
Let PQ be the given line segment and l be a given line. 1. Mark a point 0 on the line l.
2. Open out the compasses and adjust so that the steel end is on A and the pencil end is A on B.
3. Transfer the compasses to the line l without disturbing their opening so that the steel end is on 0.
4. With the pencil end make a small stroke on the line l to cut it at the point P.
Then, the fine segment OP so obtained = the given line segment AB.

Ex 14.3 Class 6 Maths Question 2.
Given some line segment $\overline { AB }$, whose length you do not know, construct $\overline { PQ }$ such that the length of $\overline { PQ }$ is twice that of $\overline { AB }$.
Solution:
Steps of Construction:
Let AB be the given line segment.

1. Draw any line l and make a point 0 on it.
2. Open out the compasses in such way that the steel end is on A and the pencil end is on B.
3. Transfer the compasses without disturbing their opening to the line l so that the steel end is on O.
4. With the pencil end make a small stroke on -the line l to cut it at the point P.
5. Repeat the steps 3 and 4 with same opening having P as the initial point and Q as the terminal point.
Then, the segment OQ = OP + PQ = AB + AB= 2 AB.

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